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6t^2-42t+36=0
a = 6; b = -42; c = +36;
Δ = b2-4ac
Δ = -422-4·6·36
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{900}=30$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-42)-30}{2*6}=\frac{12}{12} =1 $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-42)+30}{2*6}=\frac{72}{12} =6 $
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